Inserting the inductor in the form of a magnetic coupling

[AF2000]

Hi
How can I use 3 inductors as a magnetic coupling in Proteus?
In the appendix,
I have given an example of Proteus below.
I do not understand the introduction of reciprocal inductance in Proteus and the method of labeling
My goal is to set the values ​​of the inductance matrix in the proteus.
please guide me .

[Ettore]

The number of mutual coefficients is given by to the combination without repetition of the inductors number, n: C(n,k)=n!/(2*(n-2)!).
With 2 inductors, L1, L2, we have one only mutual coefficient K=L12, so your solution is wrong.
The property MUTUAL_B=1 - or MUTUAL_L2 in the new syntax - has to be added to L1:A. L1:B won't need any mutual coefficient.

In the case of three inductors the mutual coefficients combination will have to be L12, L13 and L23. So, if L1:A, L1:B and L1:C are the case then add the coefficients MUTUAL_B=1 and MUTUAL_C=1 to L1:A (L12 and L13) and MUTUAL_C=1 to L1:B (L23). L1:C must not have any coefficient.

If you require any further support please send in your customer number to support@labcenter.com

[AF2000]

Thanks for much.
Sorry
I have attached the circuit file I want to simulate and the inductance matrix I want to import.
I want to figure out the voltage of the three nodes using the probe Show.(In the graph mode section, analog analysis)
The application gives an error .
Is the part closed incorrectly?
Is the inductance matrix entered correctly?

please guide me .

[Ettore]

I hate to tell it but you are definitely using an illegal copy of Proteus and in such the case I cannot provide you with any further support.
Please purchase a licence from https://www.labcenter.com/pricing/comm/